Ten signals, each requiring 4000 Hz, are multiplexed onto a single channel using FDM. How much minimum bandwidth is required for the multiplexed channel? Assume that the guard bands are 400 Hz wide.
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For FDM, calculate total bandwidth as (number of signals × bandwidth per signal) + guard bands.
Each signal requires 4000 Hz. For 10 signals, the bandwidth without guard bands totals 10 × 4000 = 40000 Hz. With the addition of guard bands, calculated as 9 × 400 = 3600 Hz, the overall bandwidth is 40000 + 3600 = 43600 Hz.