Step 1: Conceptual Foundation: This exercise focuses on calculating elementary probabilities associated with a single roll of a standard six-sided die. The set of all possible outcomes, known as the sample space, is S = {1, 2, 3, 4, 5, 6}. The total count of these outcomes is 6. The probability of any given event E is determined by the formula: P(E) = (Number of favorable outcomes) / (Total number of outcomes).
Step 2: Methodology: We will assess the probability for each of the given statements (A), (B), (C), and (D) to ascertain their validity.
Step 3: Detailed Analysis:
(A) Probability of rolling a number greater than 4:
The outcomes exceeding 4 are {5, 6}. This yields 2 favorable outcomes.
P(A) = \( \frac{2}{6} = \frac{1}{3} \). This statement is correct.
(B) Probability of rolling a number greater than or equal to 4:
The outcomes meeting or exceeding 4 are {4, 5, 6}. This provides 3 favorable outcomes.
P(B) = \( \frac{3}{6} = \frac{1}{2} \). The assertion in the statement is \( \frac{1}{3} \), rendering this statement incorrect.
(C) Probability of rolling a number less than or equal to 3:
The outcomes not exceeding 3 are {1, 2, 3}. This results in 3 favorable outcomes.
P(C) = \( \frac{3}{6} = \frac{1}{2} \). This statement is correct.
(D) Probability of rolling a number less than or equal to 6:
The outcomes not exceeding 6 are {1, 2, 3, 4, 5, 6}. This comprises 6 favorable outcomes.
P(D) = \( \frac{6}{6} = 1 \). This represents a certain event. This statement is correct.
The statements identified as correct are (A), (C), and (D).
Step 4: Conclusion:
The correct option corresponds to the selection encompassing (A), (C), and (D) exclusively.