Each bit independently remains unchanged with probability \(0.99\). For the entire 5-bit message to arrive without any error, every bit must remain unchanged simultaneously.
The likelihood of this happening is:
\(0.99 \times 0.99 \times 0.99 \times 0.99 \times 0.99 = 0.99^5\)
Evaluating this expression gives:
\(0.99^5 \approx 0.95099\)
Hence, the probability that the message is delivered without any error is \(\boxed{0.951}\) (rounded to three decimal places).
P and Q play chess frequently against each other. Of these matches, P has won 80% of the matches, drawn 15% of the matches, and lost 5% of the matches.
If they play 3 more matches, what is the probability of P winning exactly 2 of these 3 matches?
If A and B are two events such that \( P(A \cap B) = 0.1 \), and \( P(A|B) \) and \( P(B|A) \) are the roots of the equation \( 12x^2 - 7x + 1 = 0 \), then the value of \(\frac{P(A \cup B)}{P(A \cap B)}\)