Question:medium

Sum of squares of two numbers is 3341 and difference is 891. Find numbers.

Show Hint

When both sum and difference of squares are given, add the equations first to eliminate one variable quickly.
Updated On: Jul 14, 2026
  • 35 and 46
  • 35 and 50
  • 40 and 55
  • 45 and 60
Show Solution

The Correct Option is A

Solution and Explanation

Step 1: Let \( x^2 = A \) and \( y^2 = B \), so the two given conditions become \( A+B=3341 \) and \( A-B=891 \).

Step 2: For any two numbers whose sum and difference are known, the larger equals half the sum plus half the difference, and the smaller equals half the sum minus half the difference: \( A = \frac{3341+891}{2} = \frac{4232}{2}=2116 \), and \( B = \frac{3341-891}{2}=\frac{2450}{2}=1225 \).

Step 3: Taking square roots: \( x=\sqrt{2116}=46 \) and \( y=\sqrt{1225}=35 \).
\[ \boxed{35 \text{ and } 46} \]
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