Step 1: Understanding the Concept:
This is a logical syllogism problem. We can solve this by drawing a Venn diagram or analyzing the logical statements to test the validity of each conclusion regarding the sets.
Step 2: Key Formula or Approach:
Use Set Theory logic: "No A is B" means $A \cap B = \emptyset$. "Some A are B" means $A \cap B \neq \emptyset$. Apply these to test the truth of the given options.
Step 3: Detailed Explanation:
Let's break down the given statements:
Some cashmere jackets are fashionable: The set of Cashmere Jackets ($C$) and Fashionable items ($F$) have an intersection ($C \cap F \neq \emptyset$).
Some cashmere jackets are not suede jackets: There exist items in $C$ that are outside the set of Suede Jackets ($S$).
No suede jacket is fashionable: The set of Suede Jackets ($S$) and Fashionable items ($F$) are entirely disjoint, meaning they have no intersection at all ($S \cap F = \emptyset$).
Now let's evaluate the given conclusions:
(A) Some fashionable jackets are not suede jackets: From statement 3, we know {absolutely no} suede jacket is fashionable. Consequently, {all} fashionable jackets are non-suede. Since statement 1 confirms that fashionable jackets do exist (at least the cashmere ones), stating that "some fashionable jackets are not suede" is a logically true statement (it's a subset of the truth that "all are not suede").
(B) All cashmere jackets are fashionable: Statement 1 only says "Some", so we cannot assume "All".
(C) Some suede jackets are cashmere jackets: While it's a possibility based on the Venn diagram, it is not a definite conclusion strictly derived from "Some cashmere are not suede".
(D) No cashmere jacket is fashionable: This directly contradicts Statement 1.
Step 4: Final Answer:
The only correct and logically sound conclusion is (A).