Question:medium

Standard deviation of first \( n \) odd natural numbers is:

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The variance of an Arithmetic Progression with common difference \( d \) is \( \sigma^2 = \frac{(n^2-1)d^2}{12} \). For odd numbers, \( d=2 \). Thus, \( \sigma^2 = \frac{(n^2-1)4}{12} = \frac{n^2-1}{3} \).
Updated On: May 1, 2026
  • \( \sqrt{n} \)
  • \( \sqrt{\frac{(n+2)(n+1)}{3}} \)
  • \( \sqrt{\frac{n^2 - 1}{3}} \)
  • \( n \)
  • \( 2n \)
Show Solution

The Correct Option is C

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