Standard deviation of first \( n \) odd natural numbers is:
Show Hint
The variance of an Arithmetic Progression with common difference \( d \) is \( \sigma^2 = \frac{(n^2-1)d^2}{12} \). For odd numbers, \( d=2 \). Thus, \( \sigma^2 = \frac{(n^2-1)4}{12} = \frac{n^2-1}{3} \).