Question:medium

Spin Quantum number of \( ^{13}C \) NMR is:

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- NMR-active nuclei have a nonzero spin quantum number (\( I \neq 0 \)). - \( ^{13}C \) has \( I = \frac{1}{2} \), making it ideal for NMR spectroscopy. - \( ^{12}C \) is NMR inactive because it has \( I = 0 \).
Updated On: Jul 14, 2026
  • \( \frac{1}{4} \)
  • \( \frac{1}{2} \)
  • \( \frac{3}{2} \)
  • \( \frac{1}{3} \)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept.
A nucleus's spin quantum number comes from how its protons and neutrons pair up, and only certain values, 0, \( \frac{1}{2} \), 1, \( \frac{3}{2} \), and so on, are physically possible.

Step 2: Key Approach.
Count the protons and neutrons in carbon-13 and use the general pairing rule to work out its spin state, rather than treating this as an arbitrary fact to memorise.

Step 3: Detailed Explanation.
Carbon-13 has 6 protons and 7 neutrons, for a total of 13 nucleons, an odd number overall.
When a nucleus has an even number of one type of nucleon and an odd number of the other, as here with 6 even protons and 7 odd neutrons, the resulting spin quantum number works out to the simplest nonzero half-integer value, \( \frac{1}{2} \).
This is the same spin state carried by the hydrogen-1 nucleus, which is why carbon-13 NMR and proton NMR share broadly similar, well-behaved signal splitting patterns.
Values like \( \frac{1}{4} \), \( \frac{1}{3} \), or \( \frac{3}{2} \) either fall outside the allowed set entirely or belong to nuclei with a different, more complex nucleon pairing.

Step 4: Final Answer.
The spin quantum number of \( ^{13}C \) is \( \boxed{\frac{1}{2}} \).
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