Question:medium
Solid sphere is rotating about an axis as shown in figure. If the radius of the sphere is 5 cm, then radius of gyration about that axis will be \(\sqrt{x}\) cm. The value of x is
Solid sphere is rotating about an axis as shown in figure. If the radius of the sphere is 5 cm, then radius of gyration about that axis will be \(\sqrt{x}\) cm. The value of x is
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Use the parallel axis theorem with the axis 10 cm from the centre.
Updated On: Oct 1, 2026
- \(100\)
- \(110\)
- \(120\)
- \(140\)
Show Solution
The Correct Option is B
Solution and Explanation
Step 1: Formula
$k^2 = \frac{I}{M} = \frac25R^2 + d^2$.
Step 2: Numbers
$\frac25\times25 + 100 = 10 + 100 = 110$. Option (B).
Final Answer:
x = 110. \[ \boxed{\text{(B)}\ 110} \]
$k^2 = \frac{I}{M} = \frac25R^2 + d^2$.
Step 2: Numbers
$\frac25\times25 + 100 = 10 + 100 = 110$. Option (B).
Final Answer:
x = 110. \[ \boxed{\text{(B)}\ 110} \]
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