Step 1: Formula-first
At constant volume $Q=\Delta U=nC_v\Delta T$.
Step 2: Substitution
$n=6$, $C_v=C_p-R=6$, $\Delta T=15$.
Step 3: Result
$\Delta U=6\times 6\times 15=540$ cal, option (D).
Final Answer:
The internal energy increases by 540 cal.
\[ \boxed{\text{(D) }540\ \text{cal}} \]