Question:medium

Silicon (IV) chloride on hydrolysis gives an acid \(X\). The number of \(-OH\) groups present in \(X\) is

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Hydrolysis of \(SiCl_4\) produces orthosilicic acid, \[ Si(OH)_4 \; (H_4SiO_4) \] which contains four hydroxyl groups.
Updated On: Jun 18, 2026
  • 2
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The Correct Option is D

Solution and Explanation

Step 1: Write and count products of hydrolysis.
SiCl₄ + 4H₂O → Si(OH)₄ + 4HCl. Orthosilicic acid Si(OH)₄ has exactly 4 hydroxyl groups attached to the central silicon.

Step 2: Final Answer:

4 (option 4).
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