Step 1: Compute all three side ratios first.
Instead of comparing two triangles at a time, let us find the ratio of the two given sides for all three triangles up front, then match them in one pass. Recall the SAS similarity rule: two triangles are similar if one pair of included angles is equal and the sides forming that angle are in the same ratio.
Step 2: Ratio for $\Delta RPQ$.
Sides $PR = 6\text{ cm}$ and $PQ = 4\text{ cm}$, included angle $\angle P = 60^{\circ}$.
\[ \frac{PR}{PQ} = \frac{6}{4} = 1.5 \]
Step 3: Ratio for $\Delta XZY$.
Sides $XZ = 9\text{ cm}$ and $YZ = 6\text{ cm}$, included angle $\angle Z = 60^{\circ}$.
\[ \frac{XZ}{YZ} = \frac{9}{6} = 1.5 \]
Step 4: Ratio for $\Delta LMN$.
Sides $LN = 3\text{ cm}$ and $MN = 4\text{ cm}$, included angle $\angle N = 60^{\circ}$.
\[ \frac{LN}{MN} = \frac{3}{4} = 0.75 \]
Step 5: Match the ratios.
All three included angles equal $60^{\circ}$, so the deciding factor is the side ratio. $\Delta RPQ$ gives $1.5$ and $\Delta XZY$ also gives $1.5$, an exact match. $\Delta LMN$ gives $0.75$, which does not match either of the other two, so it is not similar to them.
Final Answer:
Since the included angles are equal and the ratios of the sides forming them match only for $\Delta RPQ$ and $\Delta XZY$, these two triangles are similar. This is option (A).
\[ \boxed{\Delta RPQ \sim \Delta XZY} \]