Question:medium
Seven people, A, B, C, D, E, F and G, want to go boating. Only two boats are available, and their seating must follow these rules:
(I) A will go in the same boat as E.
(II) F cannot go in the same boat as C, unless D also joins them.
(III) Neither B nor C can be placed in the same boat as G.
(IV) A single boat can carry a maximum of four people.
If F and B are seated in one boat, which of the following statements is true?
Seven people, A, B, C, D, E, F and G, want to go boating. Only two boats are available, and their seating must follow these rules:
(I) A will go in the same boat as E.
(II) F cannot go in the same boat as C, unless D also joins them.
(III) Neither B nor C can be placed in the same boat as G.
(IV) A single boat can carry a maximum of four people.
If F and B are seated in one boat, which of the following statements is true?
(I) A will go in the same boat as E.
(II) F cannot go in the same boat as C, unless D also joins them.
(III) Neither B nor C can be placed in the same boat as G.
(IV) A single boat can carry a maximum of four people.
If F and B are seated in one boat, which of the following statements is true?
Show Hint
Work out first which two people are always stuck together because of the G restriction, then see who rule II forces to join F.
Updated On: Jul 14, 2026
- G is in the other boat
- D is in the other boat
- C is in the other boat
- E is with F and B in one boat
Show Solution
The Correct Option is A
Solution and Explanation
Instead of building the seating step by step, check each option against the rules once the F-B boat is fixed.
- G is in the other boat: Rule III keeps G away from B and C. Since B and C sit with F, and rule II forces D to join them once F and C are together, G cannot be in that boat, so it must sit in the other one.
- D is in the other boat: Rule II says F and C need D with them once they share a boat. Since F, B and C already sit together, D is forced into that same boat, not the other one, so this option fails.
- C is in the other boat: B never sits apart from C, since both are barred from G's boat, and with only two boats that leaves one shared boat for them. Since F is with B, C is with F too, not in the other boat.
- E is with F and B in one boat: Rule I locks A and E together. Adding E to the F, B, C, D boat would make five people, which breaks the four person cap in rule IV, so E and A must be in the second boat instead.
Only the first statement survives every rule, so the boat with F and B carries B, C, D, F while A, E, G occupy the other boat.
Let's summarize:
- B and C are always together, away from G.
- F with C forces D into the same boat.
- That fills the four person limit, pushing A, E, G into the second boat.
The other boat carries G along with A and E, so option 1 is correct.
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