Question

Series LCR circuit containing an a.c. source of 100V has a inductor and a capacitor of reactance \(24 \Omega\) and \(16 \Omega\) respectively. If a resistance of \(6 \Omega\) is connected in series, then the potential difference across the series combination of inductor and capacitor only is

• A. \(80\text{V}\)
• B. \(8\text{V}\)
• C. \(40\text{V}\)
• D. \(20\text{V}\)

Hint:

Find the current from the impedance, then multiply by the net reactance.

Answer 1

The Correct Option is A

Step 1: Individual voltages
$V_L = 10\times24 = 240$ V and $V_C = 10\times16 = 160$ V, which are in opposite phase.

Step 2: Combination
$240-160 = 80$ V. Option (A).

Final Answer:
80 V. \[ \boxed{\text{(A)}\ 80\ \text{V}} \]