Selected data points of the step response of a stable first-order linear time-invariant (LTI) system are given below. The closest value of the time-constant, in sec, of the system is:
| Time (sec) | 0.6 | 1.6 | 2.6 | 10 | ∞ |
|---|---|---|---|---|---|
| Output | 0.78 | 1.65 | 2.18 | 2.98 | 3 |
y(t) = A(1 - e-t/τ)
where A = 3 is the final value and τ is the time constant. We can estimate τ using a data point.Using the value at t = 1.6, we have:
y(1.6) = 1.65 = 3(1 - e-1.6/τ)
⇒ 1.65 / 3 = 1 - e-1.6/τ
⇒ e-1.6/τ = 1 - 0.55 = 0.45
⇒ -1.6 / τ = ln(0.45)
⇒ τ = 1.6 / -ln(0.45) ≈ 1.6 / 0.798 ≈ 2.0
A continuous time periodic signal \( x(t) \) is given by: \[ x(t) = 1 + 2\cos(2\pi t) + 2\cos(4\pi t) + 2\cos(6\pi t) \] If \( T \) is the period of \( x(t) \), then evaluate: \[ \frac{1}{T} \int_0^T |x(t)|^2 \, dt \quad {(round off to the nearest integer).} \]

The Nyquist plot of a strictly stable \( G(s) \), having the numerator polynomial as \( (s - 3) \), encircles the critical point \(-1\) once in the anti-clockwise direction. Which one of the following statements on the closed-loop system shown in the figure is correct?
