Question:medium

Samesh walks 12 km North, turns right and walks 4 km, then turns right and walks 9 km. How far and in what direction is he from his starting point?

Show Hint

Direction problems with distances often form a right-angled triangle. Use the Pythagorean theorem ($a^2 + b^2 = c^2$) to find the displacement.
Updated On: Jun 15, 2026
  • 10 km North
  • 10 km North-East
  • 5 km North
  • 5 km North-East
  • 6 km North
Show Solution

The Correct Option is D

Solution and Explanation

Step 1: Understanding the Concept:
Use the Pythagorean theorem ($a^2 + b^2 = c^2$) to find the displacement from the origin.
Step 2: Identifying the Vector of Change:
- Move 1: 12 km North. - Move 2: 4 km East (Turn right from North). - Move 3: 9 km South (Turn right from East).
Step 3: Calculation:
- Net Vertical distance = $12 \text{ (North)} - 9 \text{ (South)} = 3 \text{ km North}$. - Net Horizontal distance = $4 \text{ km East}$. - Distance = $\sqrt{3^2 + 4^2} = \sqrt{9 + 16} = \sqrt{25} = 5 \text{ km}$. - Direction: Since he is North and East of the start, it is North-East.
Step 4: Final Answer:
Samesh is 5 km North-East from the starting point. Thus, the correct option is (d).
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