Work with percentages instead of raw variables to double-check the result from a different angle.
Let A's salary $=3x$ and B's salary $=4x$. Let A's expenditure $=4y$ and B's expenditure $=5y$.
Statement I fixes B's saving as a fraction of B's salary: saving of B $= 4x - 5y = 0.25(4x) = x$. This single equation relates $x$ and $y$ directly: $5y = 3x$, so $y = 0.6x$.
Now find A's saving using this relation:
\[\text{Saving of A} = 3x - 4y = 3x - 4(0.6x) = 3x - 2.4x = 0.6x\]The savings ratio is then:
\[\text{Saving of A} : \text{Saving of B} = 0.6x : x = 3 : 5\]This ratio has no leftover unknown in it, since the variable $x$ cancels completely, so Statement I alone answers the question on its own, regardless of the actual salary figures.
Statement II, by contrast, only tells us $4x = 2500$, fixing $x = 625$ in rupees. That pins down both salaries exactly, but expenditure was defined only through the separate variable $y$, and nothing in Statement II constrains $y$. Infinitely many values of $y$ remain possible, each giving a different savings ratio, so Statement II alone cannot answer the question.
Therefore Statement I alone is sufficient while Statement II alone is not, confirming option (1): the ratio of savings is \(\boxed{3:5}\), obtainable from Statement I alone.