Question

Runway length after elevation and temperature correction is 700 m. The effective gradient is 1%. Find the final corrected length.

Hint:

In problems involving correction factors such as gradient, use the appropriate formulas to adjust the given values. For gradients, the correction is often calculated using the square root of \( 1 - \text{gradient} \).

Answer 1

The final corrected length of the runway can be found using the formula for runway length correction due to gradient: \[ L_{\text{final}} = \frac{L_{\text{corrected}}}{\sqrt{1 - G}} \] Where: - \( L_{\text{corrected}} = 700 \, \text{m} \) is the length after elevation and temperature correction, - \( G = 1\% = 0.01 \) is the effective gradient. Substitute the values: \[ L_{\text{final}} = \frac{700}{\sqrt{1 - 0.01}} = \frac{700}{\sqrt{0.99}} \approx 700 \times 1.005 \] \[ L_{\text{final}} \approx 705 \, \text{m} \] Thus, the final corrected runway length is approximately \( 705 \, \text{m} \).