Question:medium

Read the following statements:

A. When small temperature difference between a liquid and its surrounding is doubled, the rate of loss of heat of the liquid becomes twice.

B. Two bodies P and Q having equal surface areas are maintained at temperature 10°C and 20°C. The thermal radiation emitted in a given time by P and Q are in the ratio 1 : 1.15.

C. A carnot Engine working between 100 K and 400 K has an efficiency of 75%.

D. When small temperature difference between a liquid and its surrounding is quadrupled, the rate of loss of heat of the liquid becomes twice.

Choose the correct answer from the options given below

Updated On: Mar 20, 2026
  • A, B, C only
  • A, B only
  • A, C only
  • B, C, D only
Show Solution

The Correct Option is A

Solution and Explanation

To determine which of the statements are correct, let's analyze each one step by step:

  1. Statement A: "When the small temperature difference between a liquid and its surrounding is doubled, the rate of loss of heat of the liquid becomes twice."
    • This statement refers to Newton's Law of Cooling, which states that the rate of loss of heat of a body is directly proportional to the difference in temperature between the body and its surroundings, q \propto \Delta T.
    • Thus, if the temperature difference is doubled, the rate of heat loss also doubles. Hence, this statement is correct.
  2. Statement B: "Two bodies P and Q having equal surface areas are maintained at temperatures 10°C and 20°C. The thermal radiation emitted in a given time by P and Q are in the ratio 1 : 1.15."
    • The Stefan-Boltzmann Law states that the power emitted by a black body per unit area is directly proportional to the fourth power of the temperature: E = \sigma T^4.
    • To find the ratio of thermal radiation emitted, convert the temperatures to Kelvin: 10°C = 283 K and 20°C = 293 K.
    • The ratio of emitted power is \frac{293^4}{283^4} \approx 1.15. Hence, this statement is correct.
  3. Statement C: "A Carnot Engine working between 100 K and 400 K has an efficiency of 75%."
    • The efficiency of a Carnot Engine is given by \eta = 1 - \frac{T_C}{T_H}, where T_C is the cold reservoir temperature and T_H is the hot reservoir temperature.
    • Substituting the values: \eta = 1 - \frac{100}{400} = 1 - 0.25 = 0.75 or 75%.
    • Therefore, this statement is correct.
  4. Statement D: "When small temperature difference between a liquid and its surrounding is quadrupled, the rate of loss of heat of the liquid becomes twice."
    • According to Newton's Law of Cooling, if the temperature difference is quadrupled, the rate of heat loss should also quadruple, not double.
    • Thus, this statement is incorrect.

Based on the analysis, the correct statements are A, B, and C. Therefore, the correct answer is A, B, C only.

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