Question:medium

Read the following passage carefully and answer the question that follows: A leather factory produces two kinds of bags, standard and deluxe. The profit margin is Rs. 20 on a Standard bag and Rs. 30 on a deluxe bag. Every bag must be processed on machine A and on machine B. The processing times per bag on the two machines are as follows: |c|c|c| Time Required in Hours per Bag & Machine A & Machine B
Standard Bag & 4 & 6
Deluxe Bag & 5 & 10
The total time available on machine A is 700 hours and on machine B is 1250 hours. Among the following production plans, which one meets the machine availability constraints and maximizes the profits for the factory?

Show Hint

Check each options against the constraints and calculate profit to find the maximum.
Updated On: Jun 15, 2026
  • Standard 100 bags, Deluxe 60 bags
  • Standard 75 bags, Deluxe 80 bags
  • Standard 100 bags, Deluxe 10 bags
  • Standard 60 bags, Deluxe 90 bags
  • Standard 50 bags, Deluxe 100 bags
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Understanding the Concept:
This is a Linear Programming problem. We need to check which plan stays within the machine hour limits while providing the highest profit.
Step 2: Key Formula or Approach:
Constraints: 1. Machine A: \(4S + 5D \le 700\) 2. Machine B: \(6S + 10D \le 1250\) Profit = \(20S + 30D\).
Step 3: Detailed Explanation:
Let's check the options for feasibility: - (A) 100S, 60D: \(4(100)+5(60)=700\) (OK); \(6(100)+10(60)=1200\) (OK). Profit = \(2000+1800=3800\). - (B) 75S, 80D: \(4(75)+5(80)=300+400=700\) (OK); \(6(75)+10(80)=450+800=1250\) (OK). Profit = \(1500+2400=3900\). - (D) 60S, 90D: \(4(60)+5(90)=240+450=690\) (OK); \(6(60)+10(90)=360+900=1260\) (NOT OK). - (E) 50S, 100D: \(4(50)+5(100)=700\) (OK); \(6(50)+10(100)=1300\) (NOT OK). Comparing valid plans: Plan B (3900) is higher than Plan A (3800).
Step 4: Final Answer:
Standard 75 bags, Deluxe 80 bags maximizes profit.
Was this answer helpful?
0

Top Questions on Miscellaneous