Sec. butyl alcohol
The reaction between acetone and methylmagnesium chloride followed by hydrolysis is a classic example of a Grignard reaction. Here is the step-by-step explanation of the process:
Acetone, a ketone, reacts with methylmagnesium chloride, a Grignard reagent. The general reaction mechanism involves the nucleophilic attack of the Grignard reagent on the carbonyl carbon.
The nucleophile (methyl group, \(\text{-CH}_3\)), from methylmagnesium chloride, attacks the electrophilic carbon atom in acetone's carbonyl group (C=O).
This step results in the formation of an intermediate magnesium alkoxide complex.
The intermediate can be represented as:
\(\text{(CH}_3)_2\text{C-O-MgCl}\)
Hydrolysis of the magnesium alkoxide intermediate yields the corresponding alcohol. In this case, the Tertiary butyl alcohol (\(\text{(CH}_3)_3\text{C-OH}\)) is formed.
Therefore, the product formed from the reaction between acetone and methylmagnesium chloride followed by hydrolysis is tert. butyl alcohol.
Consider the following molecules:
The order of rate of hydrolysis is: