Question:easy
Propyne on reaction with water in presence of \(40\%\) sulphuric acid and \(1\%\) mercuric sulphate forms
Propyne on reaction with water in presence of \(40\%\) sulphuric acid and \(1\%\) mercuric sulphate forms
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Alkynes hydrate by Kucherov reaction to ketones, following Markovnikov.
Updated On: Oct 1, 2026
- Propan-1-ol
- Propan-2-ol
- Propanone
- Propanal
Show Solution
The Correct Option is C
Solution and Explanation
Step 1: Markovnikov addition:
The middle carbon is more substituted, so $-\text{OH}$ attaches there.
Step 2: Tautomerism:
The enol $\text{CH}_3\text{C(OH)=CH}_2$ shifts H to the terminal carbon, converting to the keto form $\text{CH}_3\text{COCH}_3$.
Final Answer:
The product is propanone, option (C). \[ \boxed{\text{Propanone}} \]
The middle carbon is more substituted, so $-\text{OH}$ attaches there.
Step 2: Tautomerism:
The enol $\text{CH}_3\text{C(OH)=CH}_2$ shifts H to the terminal carbon, converting to the keto form $\text{CH}_3\text{COCH}_3$.
Final Answer:
The product is propanone, option (C). \[ \boxed{\text{Propanone}} \]
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