Propene to 1-Iodopropane
The conversion of propene to 1-iodopropane is achieved through an electrophilic addition reaction utilizing hydroiodic acid (HI).
The pi bond in propene undergoes reaction with HI. Per Markovnikov's rule, the hydrogen atom of HI bonds to the alkene carbon bearing more hydrogen atoms, while the iodine atom attaches to the other alkene carbon, yielding the target compound.
\( \text{CH}_2=\text{CHCH}_3 + \text{HI} \rightarrow \text{CH}_3\text{CH}_2\text{CH}_2\text{I} \)
Product: 1-iodopropane
Given below are two statements:
Statement (I): Alcohols are formed when alkyl chlorides are treated with aqueous potassium hydroxide by elimination reaction.
Statement (II): In alcoholic potassium hydroxide, alkyl chlorides form alkenes by abstracting the hydrogen from the $ \beta $-carbon.
In the light of the above statements, choose the most appropriate answer from the options given below: