Question:medium

Products of the following reaction:
hydrolysis

Updated On: Apr 28, 2026
  • CH3CHO + CH3CH2CHO

  • CH3COOH + CH3COCH3

  • CH3COOH + HOOC . CH2CH3

  • CH3COOH + CO2

Show Solution

The Correct Option is C

Solution and Explanation

To determine the products of the given reaction, let's analyze the reaction step-by-step:

The given reaction involves ozonolysis of alkenes followed by hydrolysis. The structure is a representation of an alkene: 

\(CH_3 - C = C - CH_2CH_3\)

  1. The first step is ozonolysis, where ozone \((O_3)\) breaks the double bond to form a molozonide, which rearranges to an ozonide.
  2. Upon hydrolysis, the ozonide breaks down into carbonyl compounds. In this case, since the double bond is between the second and third carbon atoms, the products formed are:
    • Acetic acid \((CH_3COOH)\)
    • Propanoic acid \((HOOC \cdot CH_2CH_3)\)

Thus, the correct answer is CH3COOH + HOOC . CH2CH3.

Let's eliminate the other options to ensure correctness:

  1. CH3CHO + CH3CH2CHO: These are aldehydes which do not form from the given ozonolysis process.
  2. CH3COOH + CH3COCH3: These products are incorrect as they involve an additional oxidation state.
  3. CH3COOH + CO2: CO2 is not formed from simple ozonolysis.

Conclusion: The reaction products are correctly identified as acetic acid and propanoic acid, matching the mechanism of ozonolysis followed by hydrolysis.

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