The Correct Option is B
Solution and Explanation
The reaction presented is an elimination reaction, employing alcoholic KOH as the base. These conditions promote alkene formation through an E2 mechanism. The elimination proceeds via the abstraction of a beta-hydrogen, resulting in the formation of the most stable (i.e., more substituted) alkene as the principal product. The product obtained in this instance is a highly substituted alkene, thus identifying option (2) as the correct selection.
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Given below are two statements:
Statement (I): Alcohols are formed when alkyl chlorides are treated with aqueous potassium hydroxide by elimination reaction.
Statement (II): In alcoholic potassium hydroxide, alkyl chlorides form alkenes by abstracting the hydrogen from the $ \beta $-carbon.
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