Question:medium

Pressure (p) as function of radius (r) and time (t) can be found from the analytical solution of radial diffusivity equation for homogenous and isotropic reservoir following Darcy law. For this solution, if dp/dt is treated as constant, which of the following correctly describe(s) the state(s) of pressure change?

Show Hint

Ask where dp/dt does not change with time, only pseudo-steady (constant nonzero decline) and steady (dp/dt = 0) qualify.
Updated On: Jul 28, 2026
  • Transient
  • Pseudo-steady
  • Steady
  • Unsteady
Show Solution

The Correct Option is B, C

Solution and Explanation

Step 1: Set up the diffusivity equation and treat dp/dt as a given constant $C$:
Start from \( \frac{1}{r}\frac{\partial}{\partial r}\left(r \frac{\partial p}{\partial r}\right) = \frac{\phi \mu c_t}{k}\frac{\partial p}{\partial t} \). If $\frac{\partial p}{\partial t} = C$ is treated as a constant that does not depend on $r$ or $t$, the right hand side becomes a fixed number, and the equation reduces to an ordinary differential equation in $r$ alone, $\frac{1}{r}\frac{d}{dr}\left(r\frac{dp}{dr}\right) = \frac{\phi \mu c_t}{k} C$.
Step 2: Consider the special case $C = 0$:
If the constant $C$ is zero, then $\frac{\partial p}{\partial t} = 0$ everywhere, meaning pressure at every radius no longer changes with time. This is exactly the definition of the steady state, which happens physically when the reservoir has a constant pressure outer boundary, such as a strong active aquifer or a constant pressure injection boundary, that keeps replenishing the produced fluid. So the steady state case, option (C), is a valid solution consistent with dp/dt being constant.
Step 3: Consider the case $C \ne 0$ but still constant:
If $C$ is a fixed nonzero number, pressure is declining at the same rate everywhere in the reservoir at any instant in time, though it still varies with radius. This is exactly the pseudo-steady state, which arises physically once the pressure transient has reached a closed, no flow outer boundary and the whole reservoir volume depletes uniformly with time. So the pseudo-steady case, option (B), is also consistent with dp/dt being constant.
Step 4: Rule out the transient and unsteady options:
In transient or unsteady flow, the pressure disturbance is still propagating outward and has not stabilized, so $\frac{\partial p}{\partial t}$ genuinely depends on both $r$ and $t$ and cannot be pulled out as a single constant. This rules out options (A) and (D).
Step 5: Conclude:
Only the pseudo-steady state (constant nonzero decline rate) and the steady state (constant zero decline rate, i.e. no change) are consistent with treating dp/dt as constant.
Final Answer:
\[ \boxed{\text{(B) Pseudo-steady and (C) Steady}} \]
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