To predict the correct intermediate and product in the given reaction, we need to understand the chemical transformation involving the alkyne and the reagents provided.
The reaction starts with the alkyne H_3C-C \equiv CH .
The reagents used are H_2O, H_2SO_4, and HgSO_4. This is a typical reaction condition for the hydration of alkynes through the keto-enol tautomerism pathway.
When an alkyne is treated with water in the presence of sulfuric acid and mercuric sulfate, the reaction results in the formation of an enol as an intermediate, which quickly tautomerizes to give a more stable ketone.
The Markovnikov's rule will apply here, where the addition of water takes place such that the hydroxyl group gets attached to the most substituted carbon.
For the given substrate H_3C-C \equiv CH, the addition of water will result in an enol intermediate: H_3C-CH(OH)=CH_2, which will tautomerize to form the ketone product, H_3C-CO-CH_3 (acetone).
Thus, the correct intermediate and product based on the reaction conditions are the enol and the corresponding ketone.
The correct option is the one that represents this transformation.
Option with image is correct, showing the progression from alkyne to enol to ketone (acetone).
