Question:easy

Polar moment of inertia of a circle (\(I_{\text{0}}\)) is given by

Show Hint

Remember the distinction:
- Area Moment of Inertia (bending resistance): \(I = \frac{\pi d^4}{64}\)
- Polar Moment of Inertia (torsion resistance): \(J = 2I = \frac{\pi d^4}{32}\)
This factor of 2 is a useful shortcut for circular cross-sections.
  • \(\frac{\pi}{64} d^4\)
  • \(\frac{\pi}{32} d^4\)
  • \(\frac{\pi}{16} d^4\)
  • \(\frac{\pi}{32} d^3\)
Show Solution

The Correct Option is B

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