Step 1: Understand the Setup.
Triangle $PQR$ has vertices $P(6,0)$, $Q(2,8)$, $R(-2,4)$. $MN \parallel QR$ with $M$ on $PQ$ and $N$ on $PR$. Given $\dfrac{PM}{MQ} = \dfrac{1}{3}$, we need to show $\dfrac{MN}{QR} = \dfrac{1}{4}$.
Step 2: Find Coordinates of M Using the Section Formula.
$M$ divides $PQ$ in ratio $PM : MQ = 1 : 3$ (from $P$). By the section formula: \[ M = \left(\frac{1 \times x_Q + 3 \times x_P}{1+3},\ \frac{1 \times y_Q + 3 \times y_P}{1+3}\right) = \left(\frac{2 + 18}{4},\ \frac{8 + 0}{4}\right) = (5,\ 2) \]
Step 3: Find Coordinates of N Using the Section Formula.
Since $MN \parallel QR$ and $\dfrac{PM}{PQ} = \dfrac{1}{4}$, point $N$ divides $PR$ in the same ratio $1:3$ from $P$: \[ N = \left(\frac{1 \times (-2) + 3 \times 6}{4},\ \frac{1 \times 4 + 3 \times 0}{4}\right) = \left(\frac{-2+18}{4},\ \frac{4}{4}\right) = (4,\ 1) \]
Step 4: Calculate Length MN Using Distance Formula.
\[ MN = \sqrt{(5-4)^2 + (2-1)^2} = \sqrt{1 + 1} = \sqrt{2} \]
Step 5: Calculate Length QR Using Distance Formula.
\[ QR = \sqrt{(2-(-2))^2 + (8-4)^2} = \sqrt{4^2 + 4^2} = \sqrt{16+16} = \sqrt{32} = 4\sqrt{2} \]
Step 6: Compute the Ratio and Conclude.
\[ \frac{MN}{QR} = \frac{\sqrt{2}}{4\sqrt{2}} = \frac{1}{4} \] Hence proved. \[ \boxed{\dfrac{MN}{QR} = \dfrac{1}{4}} \]