Photoemission of electrons occurs from a metal \((\phi_0=1.96\,\text{eV})\) when light of frequency \(6.4\times10^{14}\,\text{Hz}\) is incident on it. Calculate the stopping potential.
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Remember:
\[
eV_0=K_{\max}.
\]
Therefore, if \(K_{\max}\) is given in eV, the stopping potential is numerically equal to that value in volts.