pH value of 0.001 M NaOH solution is _______.
To determine the pH value of a 0.001 M NaOH solution, we must first understand that NaOH is a strong base dissociating completely in water to produce OH- ions. This dissociation can be represented by the equation:
NaOH → Na+ + OH-
Thus, the concentration of OH- ions in the solution is 0.001 M. The pOH of a solution is calculated using the formula:
pOH = -log[OH-]
Substituting the given concentration:
pOH = -log(0.001) = 3
Given that pH + pOH = 14 for any aqueous solution at 25°C, we can find the pH as follows:
pH = 14 - pOH
pH = 14 - 3 = 11
The calculated pH value is 11, which confirms it falls within the expected range (11, 11) as specified.
K$_{sp}$ of AgBr = 4y Then, the ratio of molarity (solubility) of (1) to (2) is: