Question

P, Q, R, S, T, V and W are seven friends who left for seven destinations Delhi, Chennai, Hyderabad, Bangalore, Kolkata, Chandigarh and Jaipur, each on a different day of the week-
(K) R left for Jaipur on Monday. On Sunday, one of them left for Bangalore.
(L) T left the next day of P who left for Chandigarh and on the previous day of W.
(M) S left for Kolkata on Friday.
(N) Q did not leave for either Hyderabad or Bangalore and W left for Delhi.
What is the correct sequence of departure of the friends from Monday to Sunday?

• A. R \(\rightarrow\) P \(\rightarrow\) T \(\rightarrow\) W \(\rightarrow\) S \(\rightarrow\) Q \(\rightarrow\) V
• B. R \(\rightarrow\) T \(\rightarrow\) P \(\rightarrow\) W \(\rightarrow\) S \(\rightarrow\) Q \(\rightarrow\) V
• C. R \(\rightarrow\) W \(\rightarrow\) P \(\rightarrow\) T \(\rightarrow\) S \(\rightarrow\) V \(\rightarrow\) Q
• D. R \(\rightarrow\) W \(\rightarrow\) T \(\rightarrow\) P \(\rightarrow\) S \(\rightarrow\) V \(\rightarrow\) Q

Hint:

Consecutive-day blocks (like "P, T, W") are extremely powerful constraints in scheduling puzzles. Finding where a 3-day block fits into the schedule instantly solves more than half of the puzzle.

Answer 1

The Correct Option is A

Step 1: Lay out the week.
Seven friends leave Monday to Sunday, one per day.
Step 2: Place the fixed days.
R goes Monday (Jaipur), S goes Friday (Kolkata), and Sunday's traveller goes to Bangalore.
Step 3: Use clue (L).
P, then T, then W leave on three consecutive days; the only open run is Tuesday, Wednesday, Thursday. So P-Tue (Chandigarh), T-Wed, W-Thu (Delhi).
Step 4: Identify the leftover days.
Saturday and Sunday remain for Q and V.
Step 5: Use clue (N).
Q cannot go to Bangalore, and Sunday is the Bangalore day, so Q takes Saturday and V takes Sunday.
Step 6: Write the full order.
R, P, T, W, S, Q, V from Monday to Sunday.
\[ \boxed{\text{R} \rightarrow \text{P} \rightarrow \text{T} \rightarrow \text{W} \rightarrow \text{S} \rightarrow \text{Q} \rightarrow \text{V}} \]