OTE, PUF, QVG, RWH,?

Question

Let \[ S=\frac{1}{2!5!}+\frac{1}{3!2!3!}+\frac{1}{5!2!1!}+\cdots \text{ up to 13 terms}. \] If $13S=\dfrac{2^k}{n!}$, $k\in\mathbb{N}$, then $n+k$ is equal to

Answer 1

Position-based analysis: 1st letter sequence: O, P, Q, R, ... followed by S. 2nd letter sequence: T, U, V, W, ... followed by X. 3rd letter sequence: E, F, G, H, ... followed by I. Combining the results yields SXI, which corresponds to option (3).

OTE, PUF, QVG, RWH,?

Show Hint

The Correct Option is C

Solution and Explanation

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