Question:medium

Organic compound $C_5H_{10}$ does not give Baeyer’s reagent test. Calculate total number of structural monobromo isomers when react with $Br_2/h\nu$.

Updated On: Apr 2, 2026
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Solution and Explanation

This problem requires identifying cycloalkanes from their formula and calculating unique substitution sites for radical bromination.

LOGIC:
1. The formula $C_5H_{10}$ corresponds to a cycle or an alkene. Since it doesn't react with Baeyer's reagent ($KMnO_4$), it has no C=C bonds. It is a cycloalkane.
2. Isomers and their monobromo products:
- Cyclopentane $\rightarrow$ 1 site.
- Methylcyclobutane $\rightarrow$ 4 unique sites (methyl, $C_1$ tertiary, $C_2$ secondary, $C_3$ secondary).
- Ethylcyclopropane $\rightarrow$ 4 unique sites (methyl, $CH_2$ of ethyl, $C_{1}$ of ring, $C_{2}$ of ring).
- 1,1-dimethylcyclopropane $\rightarrow$ 2 unique sites (methyl, ring methylene).
- 1,2-dimethylcyclopropane $\rightarrow$ 3 unique structural sites (methyl, ring methine, ring methylene).
3. Total structural monobromo isomers = $1 + 4 + 4 + 2 + 3 = 14$.
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