Question:medium

One mole of a mono-atomic ideal gas is taken through a cycle ABCDA as shown in the P-V diagram, then

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Use PV = nRT to find how temperature changes for each process and then apply the first law.
Updated On: Nov 12, 2026
  • for process A to B, heat is lost and internal energy increases.
  • for process B to C, heat is lost and internal energy increases.
  • for process C to D, heat is gained and internal energy increases.
  • for process D to A, heat is gained and internal energy increases.
Show Solution

The Correct Option is C

Solution and Explanation

Step 1: Temperatures
$T_A\propto9pV$, $T_B\propto3pV$, $T_C\propto pV$, $T_D\propto9pV$.

Step 2: Check each option
A to B and B to C lose temperature, so their internal energy decreases and the statements are wrong. D to A has no change in internal energy.

Step 3: C to D
Temperature rises from $pV$ to $9pV$ at constant pressure, so energy increases and heat must be supplied.

Final Answer:
The statement about C to D is correct. \[ \boxed{\text{(C) }\text{for process C to D, heat is gained and internal energy increases}} \]
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