Question

On the magnetic meridian at some place of the Earth’s surface the vertical component of Earth’s magnetic field is \(0.433\,G\) and the dip angle is \(60^\circ\). Then the magnetic field of the Earth at this place is:

• A. \(0.5\,G\)
• B. \(1.4\,G\)
• C. \(1.7\,G\)
• D. \(0.7\,G\)

Hint:

Use \(B_V = B \sin I\) and \(B_H = B \cos I\) in Earth magnetism problems.

Answer 1

The Correct Option is A

Step 1: Vertical component relation.
B_V = B sin I, with I the dip angle.

Step 2: Inserting given data.
0.433 = B sin60° = B × 0.866.

Step 3: Solving for total field.
B = 0.433/0.866 = 0.5 G.

Step 4: Conclusion.
The total intensity is 0.5 G.