Question:hard

On opposite sides of a wide vertical vessel filled with water (density \(ρ\)), two identical holes are drilled, each having cross-section area \(A\). The height difference between holes is \(x\). The resultant force of reaction of water flowing out of vessel is (\(g\) = acceleration due to gravity)

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Each jet pushes the vessel back with force rho A v squared; the jets on opposite sides partly cancel.
Updated On: Oct 1, 2026
  • \(ρAgx\)
  • \(2ρAgx\)
  • \(3ρAgx\)
  • \(4ρAgx\)
Show Solution

The Correct Option is B

Solution and Explanation

Step 1: Approach
Use momentum flow rather than pressure, and treat each jet separately.

Step 2: Each jet
Jet speed squared is $v^2=2gh$. The momentum leaving per second is $\rho Av^2=2\rho Agh$.

Step 3: Net
The jets are on opposite sides, so the vessel feels the difference: $2\rho Ag(h_2-h_1)=2\rho Agx$.

Step 4: Answer
Option (B).

Final Answer:
Each jet gives 2 rho A g h and the opposite jets subtract, so the net is 2 rho A g x, option (B). \[ \boxed{2\rho Agx} \]
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