Question:medium
On average, how many fragments would a restriction enzyme, which recognizes a specific 5-base sequence in DNA, be expected to cleave a double-stranded bacteriophage with a genome size of 6066 bp into?
On average, how many fragments would a restriction enzyme, which recognizes a specific 5-base sequence in DNA, be expected to cleave a double-stranded bacteriophage with a genome size of 6066 bp into?
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A 4-base cutter cuts every \(4^4 = 256\) bp, a 5-base cutter cuts every \(4^5 = 1024\) bp, and a 6-base cutter cuts every \(4^6 = 4096\) bp.
Dividing 6066 bp by 1024 bp gives approximately 6, which quickly points to the correct answer.
Dividing 6066 bp by 1024 bp gives approximately 6, which quickly points to the correct answer.
Updated On: Aug 3, 2026
- About 1212
- About 120
- About 60
- About 6
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The Correct Option is D
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