Question:hard
Observe the following unbalanced reactions
\[
KO_2 \xrightarrow{\;HOH\;} X + Y\uparrow + KOH
\]
\[
KMnO_4 \xrightarrow[\text{basic medium}]{\;X\;}
Y + Z + KOH + H_2O
\]
Y and Z are respectively
Observe the following unbalanced reactions
\[
KO_2 \xrightarrow{\;HOH\;} X + Y\uparrow + KOH
\]
\[
KMnO_4 \xrightarrow[\text{basic medium}]{\;X\;}
Y + Z + KOH + H_2O
\]
Y and Z are respectively
Show Hint
Important reactions:
\[
2KO_2+2H_2O
\rightarrow
2KOH+H_2O_2+O_2
\]
and in alkaline medium,
\[
KMnO_4 + H_2O_2
\rightarrow
MnO_2 + O_2.
\]
Thus, \(H_2O_2\) acts as a reducing agent and converts purple permanganate into brown \(MnO_2\).
Updated On: Jul 29, 2026
- \(O_2,\ MnO\)
- \(O_2,\ MnO_2\)
- \(O_3,\ MnO_2\)
- \(O_3,\ MnO\)
Show Solution
The Correct Option is B
Solution and Explanation
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