Number of stereoisomers possible for the complexes, $\left[\mathrm{CrCl}_{3}(\mathrm{py})_{3}\right]$ and $\left[\mathrm{CrCl}_{2}(\mathrm{ox})_{2}\right]^{3-}$ are respectively} (py = pyridine, ox = oxalate)
To determine the number of stereoisomers for the given complexes, we analyze their geometry and possible ligand arrangements around the central metal ion.
This coordination compound features chromium (Cr) as the central metal, coordinated by three chloride ions (Cl) and three pyridine molecules (py). The complex exhibits octahedral geometry, with Cr typically bonded to six ligands in an octahedral configuration.
For octahedral complexes of the type \([\text{MA}_3\text{B}_3]\), two types of isomerism are possible:
Consequently, the complex \([\text{CrCl}_3(\text{py})_3]\) can exist as two stereoisomers: fac and mer.
The second complex involves chromium as the central metal ion, two chloride ions (Cl), and two oxalate ions (ox). Oxalate is a bidentate ligand, coordinating to the metal at two sites and forming chelate rings.
This complex also displays octahedral geometry. Stereoisomers arise from different ligand arrangements:
The complex \([\text{CrCl}_2(\text{ox})_2]^{3-}\) can exhibit:
Therefore, the complex \([\text{CrCl}_2(\text{ox})_2]^{3-}\) has 3 stereoisomers.
In summary, the number of stereoisomers for \([\text{CrCl}_3(\text{py}_3)]\) is 2, and for \([\text{CrCl}_2(\text{ox}_2)]^{3-}\) is 3. The final answer is 2 & 3.