Question

. Number of different $\text{H}$-atoms in $(\text{Y})$

• A. 4
• B. 7
• C. 12
• D. 13

Hint:

Hinsberg's test differentiates primary, secondary, and tertiary amines based on the nature of the sulfonamide product: $1^\circ$ amine product is soluble in base, $2^\circ$ amine product is insoluble, and $3^\circ$ amine does not react. Counting unique $\text{H}$ environments requires analyzing chemical equivalence and symmetry.

Answer 1

The Correct Option is B

To solve this problem, we need to analyze the chemical reaction and identify the number of different hydrogen atoms in compound (Y).

The given reaction involves:

1. C_6H_7N reacting with benzene sulphonyl chloride to form compound (Y).

This is a Hinsberg test, which is used to distinguish between primary, secondary, and tertiary amines:

• Primary amines form a sulphonamide that is soluble in alkali.
• Secondary amines form an insoluble sulphonamide.
• Tertiary amines do not react.

The compound given is aniline (C_6H_5NH_2), a primary amine. The reaction will result in a sulphonamide with the formula C_6H_5NHSO_2C_6H_5.

Now, let's count the different hydrogen atoms present:

• 5 hydrogen atoms from the benzene ring (C_6H_5).
• 1 hydrogen atom from the nitrogen (NH group).
• 1 hydrogen atom from the SO₂ group.

In total, there are 7 different hydrogen atoms.

Therefore, the correct answer is 7.