Question:medium

Number of coulombs corresponding to \(1\text{ mol}\) of electrons approximately is equal to

Show Hint

Charge of one mole of electrons is one Faraday, and \(1F\approx96500\text{ C}=9.65\times10^4\text{ C}\).
  • \(1.93\times10^5\)
  • \(9.65\times10^4\)
  • \(1.93\times10^4\)
  • \(9.65\times10^5\)
Show Solution

The Correct Option is B

Solution and Explanation

Was this answer helpful?
0