Question:medium

Nitrogen laser produces radiation at a wavelength of 337.1 nm. If the number of photons emitted is 5.6 × 1024, calculate the power of this laser.

Updated On: Jan 21, 2026
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Solution and Explanation

Given:

Wavelength, λ = 337.1 nm = 337.1 × 10−9 m
Number of photons emitted per second, n = 5.6 × 1024 s−1
Speed of light, c = 3 × 108 m s−1
Planck’s constant, h = 6.626 × 10−34 J s


Step 1: Calculate frequency of radiation

ν = c / λ

ν = (3 × 108) / (337.1 × 10−9)

ν = 8.90 × 1014 s−1


Step 2: Calculate energy of one photon

E = hν

E = (6.626 × 10−34) × (8.90 × 1014)

E = 5.90 × 10−19 J


Step 3: Calculate power of the laser

Power = Energy per second

Power = n × E

Power = (5.6 × 1024) × (5.90 × 10−19)

Power = 3.30 × 106 W


Final Answer:

Power of the nitrogen laser,
P = 3.3 × 106 W

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