Given:
For an ideal gas at STP:
Pressure, P = 1 atm = 1.013 × 105 Pa
Temperature, T = 0 °C = 273 K
Number of moles, n = 1 mol
Gas constant, R = 8.314 J mol−1 K−1
Step 1: Use the ideal gas equation
PV = nRT
For 1 mole of gas:
PV = RT
Step 2: Substitute the values
V = RT / P
V = (8.314 × 273) / (1.013 × 105)
V = 0.0224 m3
Step 3: Convert cubic metres into litres
1 m3 = 1000 L
V = 0.0224 × 1000
V = 22.4 L
Final Answer:
The molar volume of an ideal gas at STP is:
22.4 litres