Question:medium

Mohit performed an analysis of two different soil samples from two areas A and B. He recorded these results:
Soil Sample A: Lignin 40%, Sugar 0%, Chitin 45%, Nitrogen 5%
Soil Sample B: Lignin 5%, Sugar 35%, Chitin 15%, Nitrogen 45%
Which of these is true about their rate of decomposition in both the soil?

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In soil decomposition, high sugar and nitrogen content accelerate microbial activity, while high lignin content slows down the process.
Updated On: Jan 13, 2026
  • Soil A has a slower rate of decomposition than Soil B.
  • Soil A has a faster rate of decomposition than Soil B.
  • Both have the same rate of decomposition.
  • No decomposition occurs in A and B.
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The Correct Option is A

Solution and Explanation

Step 1: Organic matter composition dictates decomposition rates. Sugars decompose most rapidly, followed by chitin, with lignin decomposing slowest. Elevated nitrogen content also boosts microbial activity, accelerating decomposition.
Step 2: Soil A contains 40% lignin (slow decomposition), 0% sugar (rapid decomposition), 45% chitin, and 5% nitrogen. The high lignin percentage and low nitrogen content suggest a slower decomposition rate.
Step 3: Soil B comprises 5% lignin, 35% sugar (rapid decomposition), 15% chitin, and 45% nitrogen. The substantial sugar and nitrogen levels indicate a faster decomposition rate.
Step 4: In comparison, Soil A, possessing higher lignin and lower sugar/nitrogen levels, will exhibit a slower decomposition rate than Soil B, which benefits from increased sugar and nitrogen to support enhanced microbial activity.
Consequently, Soil A demonstrates a slower decomposition rate than Soil B.
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