Question:medium
Methane reacts with steam at \(1273K\) in the presence of nickel catalyst to form:
Methane reacts with steam at \(1273K\) in the presence of nickel catalyst to form:
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Steam reforming of methane gives syngas: \(\ce{CH4 + H2O → CO + 3H2}\).
Updated On: May 16, 2026
- \(CO\) and \(H_2\)
- \(CO_2\) and \(H_2\)
- \(CO\) and \(H_2O\)
- \(CO_2\) and \(H_2O\)
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The Correct Option is A
Solution and Explanation
Step 1: Identify the reaction.
Methane reacts with steam at high temperature in presence of nickel catalyst. This reaction is called steam reforming of methane.
Step 2: Write the chemical equation.
\[ \ce{CH4 + H2O ->[Ni][1273K] CO + 3H2} \]
Step 3: Identify the products.
The products are: \[ CO \] and: \[ H_2 \] This mixture is also called synthesis gas or syngas.
Step 4: Final answer.
Therefore, methane reacts with steam to form: \[ CO\text{ and }H_2. \]
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