Mention the type of hybridisation in the following compounds:
(a) BrF₅ (b) BrF₃
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Use the formula: H = (1)/(2)[V + M - C + A]
- V: Valence electrons of central atom
- M: Number of monovalent atoms (like F)
- C, A: Charge of cation/anion
For BrF₅: (1)/(2)[7+5] = 6 (sp³d²).
For BrF₃: (1)/(2)[7+3] = 5 (sp³d).