Question:medium

Medium 1 has the electrical permittivity \(\epsilon_1=1.5\) farad/m and occupies the region to the left of \(x=0\) plane. Medium 2 has the electrical permittivity \(\epsilon_2=2.5\) farad/m and occupies the region to the right of \(x=0\) plane. If in medium 1 \[ \vec{E}_1=(2u_x-3u_y+1u_z)\ \text{Volt/m} \] then \(\vec{E}_2\) in medium 2 is :

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At dielectric boundary: \[ E_{t1}=E_{t2} \] \[ \epsilon_1E_{n1}=\epsilon_2E_{n2} \] Tangential electric field is continuous while normal electric flux density is continuous.

Updated On: May 22, 2026

\((2.0u_x-7.5u_y+2.5u_z)\ \text{Volt/m}\)
\((2.0u_x-2.0u_y+0.6u_z)\ \text{Volt/m}\)
\((1.2u_x-3.0u_y+1.0u_z)\ \text{Volt/m}\)
\((1.2u_x-2.0u_y+0.6u_z)\ \text{Volt/m}\)

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The Correct Option is D

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The percentage of the total power carried by the sidebands of the AM wave for tone modulation when the modulation index is 0.3 is:
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Match List-I with List-II:

List-I (Modulation Schemes)	List-II (Wave Expressions)
(A) Amplitude Modulation	(I) \( x(t) = A\cos(\omega_c t + k m(t)) \)
(B) Phase Modulation	(II) \( x(t) = A\cos(\omega_c t + k \int m(t)dt) \)
(C) Frequency Modulation	(III) \( x(t) = A + m(t)\cos(\omega_c t) \)
(D) DSB-SC Modulation	(IV) \( x(t) = m(t)\cos(\omega_c t) \)

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