Question:medium

Match the types/steps involved in organizing a tournament listed in List-I with their correct associations listed in List-II:
List-I (Types/Steps involved in organising a tournament)List-II (Associations)
ABye(I)\(\frac{Number of teams +1}{2}\)
BKnock-out(II)Next highest power of 2 – number of teams
CNumber of byes(III)Team once deafeated is out of tournament
DNumber of teams in upper half of a knock-out tournament when number of teams are odd(IV)Advantage given to team in which team will not play first round and directly reaches next round

Updated On: Jan 16, 2026
  • (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
  • (A) - (II), (B) - (IV), (C) - (III), (D) - (I)
  • (A) - (III), (B) - (I), (C) - (II), (D) - (IV)
  • (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
Show Solution

The Correct Option is A

Solution and Explanation

The objective is to match the tournament organization steps in List-I with their corresponding definitions in List-II. The associations are as follows:

List-I (Types/Steps involved in organising a tournament)List-II (Associations)
A. ByeIV. Advantage given to team in which team will not play first round and directly reaches next round
B. Knock-outIII. Team once defeated is out of tournament
C. Number of byesII. Next highest power of 2 – number of teams
D. Number of teams in upper half of a knock-out tournament when number of teams are oddI. \(\frac{Number of teams +1}{2}\)

The correct pairings are:

  • (A) corresponds to (IV): A bye grants an advantage where a team skips the first round and proceeds directly to the next.
  • (B) corresponds to (III): In a knock-out format, a team is eliminated upon its first defeat.
  • (C) corresponds to (II): The quantity of byes is determined by subtracting the number of teams from the next highest power of 2.
  • (D) corresponds to (I): For an odd number of teams in a knock-out tournament, the number of teams in the upper half is calculated using the formula \(\frac{Number of teams +1}{2}\).

The definitive answer is: (A) - (IV), (B) - (III), (C) - (II), (D) - (I)

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