Question

Match the LIST-I with LIST-II 

LIST-I		LIST-II
(Saturated fatty acids found in food lipids)
A.	Heptanoic	I.	CH\(_3\)(CH\(_2\))\(_{12}\)COOH
B.	Hexanoic	II.	CH\(_3\)(CH\(_2\))\(_{4}\)COOH
C.	Pentanoic	III.	CH\(_3\)(CH\(_2\))\(_{3}\)COOH
D.	Tetranic	IV.	CH\(_3\)(CH\(_2\))\(_{5}\)COOH

Choose the most appropriate answer from the options given below:

• A. A - III, B - I, C - IV, D - II
• B. A - I, B - III, C - IV, D - II
• C. A - II, B - I, C - IV, D - II
• D. A - IV, B - II, C - III, D - I

Hint:

To quickly find the carbon count in the formula CH\(_3\)(CH\(_2\))\(_{n}\)COOH, just add 2 to 'n'. Match the count to the prefix (Pent=5, Hex=6, Hept=7, Oct=8, etc.).

Answer 1

The Correct Option is D

Step 1: Determine the carbon count for each fatty acid in LIST-I. The prefix indicates the number of carbon atoms:

A. Heptanoic acid (Hept-): 7 carbons.
B. Hexanoic acid (Hex-): 6 carbons.
C. Pentanoic acid (Pent-): 5 carbons.
D. Tetranic acid: Assumed typo for Tetradecanoic acid (Tetra-deca): 14 carbons.\end{itemize}
Step 2: Determine the carbon count for each structure in LIST-II. The general formula CH\(_3\)(CH\(_2\))\(_{n}\)COOH yields a carbon count of n + 2.

I. CH\(_3\)(CH\(_2\))\(_{12}\)COOH: 12 + 2 = 14 carbons.
II. CH\(_3\)(CH\(_2\))\(_{4}\)COOH: 4 + 2 = 6 carbons.
III. CH\(_3\)(CH\(_2\))\(_{3}\)COOH: 3 + 2 = 5 carbons.
IV. CH\(_3\)(CH\(_2\))\(_{5}\)COOH: 5 + 2 = 7 carbons.\end{itemize}
Step 3: Match names to structures based on carbon count.

A. Heptanoic (7C) \(\rightarrow\) IV (7C).
B. Hexanoic (6C) \(\rightarrow\) II (6C).
C. Pentanoic (5C) \(\rightarrow\) III (5C).
D. Tetradecanoic (14C) \(\rightarrow\) I (14C).\end{itemize}The correct matches are A - IV, B - II, C - III, and D - I, corresponding to option (4).