Question

Match the LIST-I with LIST-II \[ \begin{array}{|l|l|} \hline \textbf{LIST I (Liming materials)} & \textbf{LIST II (Neutralizing value of CCE \%)} \\ \hline A. \ \text{Calcium oxide (CaO)} & I. \ 86 \\ B. \ \text{Calcium hydroxide [Ca(OH)$_2$]} & II. \ 108.7 \\ C. \ \text{Dolomite [CaMg(CO$_3$)$_2$]} & III. \ 136 \\ D. \ \text{Basic slag (CaSiO$_3$)} & IV. \ 179 \\ \hline \end{array} \]

• A. A - I, B - II, C - III, D - IV
• B. A - I, B - III, C - II, D - IV
• C. A - IV, B - III, C - II, D - I
• D. A - III, B - IV, C - I, D - II

Hint:

Dolomite is often preferred because it supplies both calcium and magnesium while neutralizing soil acidity.

Answer 1

The Correct Option is A

Step 1: Definition of CCE.
Calcium Carbonate Equivalent (CCE) quantifies the capacity of liming materials to neutralize acidity relative to pure CaCO$_3$.
Step 2: Correspondence of Values.
- Calcium oxide (CaO): Exhibits high reactivity, with an equivalent neutralizing value of approximately 86. Therefore, A corresponds to I.
- Calcium hydroxide [Ca(OH)$_2$]: Demonstrates greater reactivity, possessing a CCE of around 108.7. Consequently, B corresponds to II.
- Dolomite [CaMg(CO$_3$)$_2$]: Has a CCE of approximately 136 due to the presence of both calcium and magnesium carbonates. Thus, C corresponds to III.
- Basic slag (CaSiO$_3$): A byproduct of steel manufacturing with a very high neutralizing value of approximately 179. Accordingly, D corresponds to IV.
Step 3: Final Alignment.
The correct pairings are A - I, B - II, C - III, D - IV.